2[5(x+y)-3(3x-2y)]=

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Solution for 2[5(x+y)-3(3x-2y)]= equation:


Simplifying
2[5(x + y) + -3(3x + -2y)] = 0
2[(x * 5 + y * 5) + -3(3x + -2y)] = 0
2[(5x + 5y) + -3(3x + -2y)] = 0
2[5x + 5y + (3x * -3 + -2y * -3)] = 0
2[5x + 5y + (-9x + 6y)] = 0

Reorder the terms:
2[5x + -9x + 5y + 6y] = 0

Combine like terms: 5x + -9x = -4x
2[-4x + 5y + 6y] = 0

Combine like terms: 5y + 6y = 11y
2[-4x + 11y] = 0
[-4x * 2 + 11y * 2] = 0
[-8x + 22y] = 0

Solving
-8x + 22y = 0

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-22y' to each side of the equation.
-8x + 22y + -22y = 0 + -22y

Combine like terms: 22y + -22y = 0
-8x + 0 = 0 + -22y
-8x = 0 + -22y
Remove the zero:
-8x = -22y

Divide each side by '-8'.
x = 2.75y

Simplifying
x = 2.75y

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